What is the molarity of a solution prepared by dissolving 2.5 grams of lino3 in sufficient water to make 60.0 ml of solution?

The molarity of the solution is 0.6

Explanation:

Molarity (M) is the number of moles of solute that are dissolved in a given volume.

The Molarity is expressed by:

Molarity is expressed in units .

Then you must know the moles that represent 2.5 grams of LiNO₃.

For that you must know the molar mass of the compound. You know the atomic mass of the elements that make up the compound, obtained from the periodic table:

So, taking into account the abundance of each element in the compound:

LiNO₃= 7 g/mol + 14 g/mol + 3*(16 g/mol)= 69 g/mol

Then a rule of three applies as follows: if 69 g of LiNO₃ is 1 mol of the compound, 2.5 g of LiNO₃ how many moles are there?

moles= 0.036

Being 60 mL = 0.06 L (1L = 1000 mL or 1 mL = 0.001 L), the molarity is calculated as:

M=0.6

The molarity of the solution is 0.6

a c d and f

just finished the assignment

i'm assuming that the correct answer is indeed the first one/ "a"..