Which statement explains why △abc is congruent to △a′b′c′ ? a you can map △abc onto △a′b′c′ by reflecting it across the x-axis and then across the y-axis, which is a sequence of rigid motions. b you can map △abc onto △a′b′c′ by translating it 6 units left and reflecting it over the x-axis, which is a sequence of rigid motions. c you can map △abc onto △a′b′c′ by translating it 2 units up and reflecting it across the y-axis, which is a sequence of rigid motions. d you can map △abc onto △a′b′c′ reflecting it across the line y = x and rotating it 90° counterclockwise about the origin, which is a sequence of rigid motions.

Its B

Step-by-step explanation:

Answer is B

Step-by-step explanation:

Observing the two triangles ABC and A'B'C' we find the following.

ABC has become the new triangle by a continuous series of translations.

First the coordinates are shifted 6 units left horizontally thus making coordinates as (x-6,y) for (x,y)

Next translation is done by changing y coordinate into negative y.  In other words, (x,y) which became (x-6,y) now transformed into (x-6,-y)

The second can also be interpreted as translation of reflection over the x axis.

Now we find that ABC is exactly matched into A"B'C"

Hence ABC is congruent to A"B'C"

y=−9/2x+10

step-by-step explanation:

let's solve for y.

0−9x−2y=−20

step 1: add 9x to both sides.

−9x−2y+9x=−20+9x

−2y=9x−20

step 2: divide both sides by -2.

−2y

−2

=

9x−20

−2

y=

−9

2

x+10