Find the equation of the straight line passing through the point (0, 1) which is perpendicular to the line y = -2x+2

This is about equation of a straight line in slope intercept form.

Equation of the straight line is y =

y = mx + c

where m is slope and c is y-intercept

A line passing through the point (0, 1)

This line is perpendicular to the line y = -2x + 2

m = -2

Thus, slope of new line = -1/-2 = 1/2

y - y1 = m(x - x1)

This gives;

y - 1 = (1/2)(x - 0)

y - 1 =

y = + 1

Read more at; link

y = x + 1

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = - 2x + 2 is in this form with slope m = - 2

given a line with slope m then the slope of a line perpendicular to it is

= - = - =

the point (0, 1 ) is the y- intercept ⇒ c = 1

y = x + 1 ← equation of perpendicular line

step-by-step explanation:

options

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: