The sum of three consecutive odd numbers is 63. what is the smallest of these numbers?

The smallest number = 19

Step-by-step explanation:

We'll call X the smallest of those odd numbers

Then x + (x+2) + (x+4) = 63

X + X + 2 + X + 4 = 63

3X + 6 = 63

3X = 63 - 6 = 57

X = 57/3 = 19

The three consecutives odd numbers are 19, 21, 23

The sum = 19+21+23 = 63

Your answer : The smallest number = 19



infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

283 square feet

step-by-step explanation:

good luck