Can anyone me with the odd numbers on my algebra 1 homework?

y =x+10

y =6x+30

substitute x+10 into the 2nd equation anywhere you see y

x+10 = 6x+30

subtract x from each side

x-x+10 = 6x-x+30

10 = 5x+30

subtract 30 from each side

10-30=5x+30-30

-20 = 5x

divide by 5 on each side

-20/5 =5x/5

-4=x

now solve for y

y=x+10

y = -4 +10

y=6

x=-4

y=6

or (-4,6)

3.  y = -3x-6

6x+5y=-30

6x+5(-3x-6) =-30

5x-15x-30=-30

-20x-30=-30

-20x=0

x=0

y = -3x-6

y=-6

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.