In a certain college, 33% of the physics majors belong to ethnic minorities. if 10 students are selected at random from the physics majors, that is the probability that no more than 6 belong to an ethnic minority?

To answer this question, we must first note that the probability of x successes in n trials is: 

P = nCx**  where p and q are the probabilities of success and failure respectively.

In this case:

p = 33% = .33

q = .67

n = 10

x = 6

Calculating *:

*=0.00026

Now the number of combinations of x in n trials is:

 nCx = 

Using the calculator to calculate for nCx from x= 1 to 6:

10C1  = 1

10C2  = 45

10C3  = 120

10C4  = 210

10C5  = 252

10C6  = 210

total nCx = 838

Substituting known values to the P equation:

P(6 or below are physics majors) = 838 * 0.00026

P(6 or below are physics majors) = 0.218

step-by-step explanation:

12475909

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!