Which exponential function goes through the points (1 , 32) and (4 , 2048)f(x) = 4(4)^xf(x)=8(2)^-xf(x) = 8(4)^xf(x) = 4(4)^-x

C. f(x) = 8 (4)^x,

-Agarvated

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2