5. factor the expression. 6x2 + 5x + 1 a)(3x + 1)(2x – 1) b)(3x – 1)(2x – 1) c)(3x – 1)(2x + 1) d)(3x + 1)(2x + 1)

The factored version of the equation 6x^2 + 5x + 1 is equal to (3x+1)(2x+1).

Step-by-step explanation:

Here is the reason why that equation is correct:

Use the FOIL method for each factored equation to see if it equals 6x^2 + 5x + 1.

(3x + 1)(2x - 1)

3x * 2x = 6x^2.

3x * -1 = -3x.

1 * 2x = 2x.

1 * -1 = -1.

6x^2 - x - 1.

(3x - 1)(2x - 1)

3x * 2x = 6x^2.

3x * -1 = -3x.

-1 * 2x = -2x.

-1 * -1 = 1.

6x^2 - 5x + 1.

(3x -  1)(2x + 1)

3x * 2x = 6x^2.

3x * 1 = 3x.

-1 * 2x = -2x.

-1 * 1 = -1.

6x^2 + x - 1.

(3x + 1)(2x + 1)

3x * 2x = 6x^2.

3x * 1 = 3x.

1 * 2x = 2x.

1 * 1 = 1.

6x^2 + 5x + 1.

D contains the only factored expression that equals 6x^2 + 5x + 1 as a result using the FOIL method.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

3/5

step-by-step explanation:

double number line is not a standard concept, so it must have been defined in your textbook. assume top line is numerator.