Mathematics, 03.07.2019 21:30 raylynnreece4939
Equation for a line with the slope of -3/4 that passes through the point (-14,4) ?
Answers: 2
![\bf (\stackrel{x_1}{-14}~,~\stackrel{y_1}{4})~\hspace{10em} slope = m\implies -\cfrac{3}{4} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-4=-\cfrac{3}{4}[x-(-14)] \\\\\\ y-4=-\cfrac{3}{4}(x+14)\implies y-4=-\cfrac{3}{4}x-\cfrac{21}{2} \\\\\\ y=-\cfrac{3}{4}x-\cfrac{21}{2}+4\implies \blacktriangleright y=-\cfrac{3}{4}x-\cfrac{13}{2} \blacktriangleleft](/tpl/images/0047/8285/d1801.png)
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Equation for a line with the slope of -3/4 that passes through the point (-14,4) ?...
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