The length of a rectangular deck is 4 times it’s width. if the deck’s perimeter is 30ft, what is the deck’s area?

Try this solution (note, this is not the shortest way):

1. if the given length is 'l' and the width is 'w', then according to the condition 4*l=w;

2. according to the condition the perimeter is 30 ft. Formula of the perimeter is P=2(l+w), then 2(l+w)=30;

3. if to substitute '4*l' instead of 'w', the formula of the perimeter (from item no. 2) will be as 2(4*l+l)=30 or 10*l=30 ⇒ l=3 ft. The length is 3 ft.!

4. if l=3 ft., then w=4*3=12 ft. The width is 12 ft.!

5. Area is

A=w*l; A=12*3=36 ft²

hi there!

the answer to this question is d: 35

step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13