If (2 − 3i) + (x + yi) = 6, what is x + yi?

(2 − 3i) + (x + yi) = 6

We add the left hand side

(2+x) + (-3+y)i = 6

6 can be written in a+ib

6 can be written as 6 + 0i

(2+x) + (-3+y)i = 6 +0i

Now we frame 2 equations

2 + x= 6

-3 + y =0

Solve the first equation

2 + x = 6

Subtract 2 from both sides

x = 4

solve the second equation

-3 + y =0

Add 3 on both sides

y= 3

So x+yi is 4+3i

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answer: it's upside down and i can't read it

step-by-step explanation: