For what value of a are the graphs of 6y=−2x+4 and 2y=ax−5 parallel? perpendicular?

a) Parallel when a = -2/3

b) Perpendicular when a = 6

Explanation:

a)  For two parallel lines slopes are equal.

  So, 6y=−2x+4 and 2y=ax−5 parallel if they are slopes equal.

  Slope of 6y=−2x+4, comparing with y = mx + c

     So, m = -2/6 = =-1/3

  For 6y=−2x+4 and 2y=ax−5 to b parallel we have slope of 2y=ax−5 equal to -1/3

   Slope of 2y=ax−5

           m = a/2

    We have a/2 = -1/3

                    a = -2/3

b) For perpendicular lines product of slope is -1.

   So we have

answer: huh

step-by-step explanation:

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for