Areflection of the pink triangle is shown. which transformation makes this reflection?
a) (x', y') = (y, x)
b) (x', y') = (x, -y)
c) (x', y') = (-x, y)
d) (x', y') = (-x, -y)
if these two figures are similar, what is the measure of angle b?
a) 35°
b) 70°
c) 95°
d) 130°
find the coordinates of the vertices of the figure after the given transformation.

reflection across the x-axis
a) u'(0, 5), p'(-1, 0), r'(3, -1), d'(3, 2)
b) u'(2, -4), p'(1, 1), r'(5, 2), d'(5, -1)
c) u'(-1, 3), p'(-2, 2), r'(2, 3), d'(2, 0)
d) u'(-4, -3), p'(-5, 2), r'(-1, 3), d'(-1, 0)

The answer is A on the last question

Step-by-step explanation:

umumumumum

im not sure

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.