48x^2 +44x=60 which of the following could be used to find the solution to the equation above? select all that apply

Because the polynomial has degree 2, we can assume that there are 2 solutions (roots), whether real or imaginary.

You can subtract 60 in order to put this in standard form

48x^2+44x-60 = 0

From there, just put a,b, and c into the quadratic formula and you're good to solve for your answers.

(-b+-sqrt(b^2-4ac))/2a

(-44+-sqrt(44^2-4(48)(-60)))/2(48)

Then solve.

There is probably a better way, but this should give you the two roots/solutions.

answer: sorry i can't you.

step-by-step explanation:

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1