An ice hockey rink is a rectangle with a perimeter of 174 meters. the length is 9 meters more than twice the width. find the length and width.

let L be the length

let W be the width

L = 9 + 2W

since the perimeter = 2L + 2W

Perimeter = 2 x (9 + 2W) + 2W

174 m = 18 + 4W + 2W

174 m = 18 + 6W

6W = 174 - 18

6W = 156

W = 156/6

W = 26

L = 9 + 2W

L = 9 + 2 x 26

L = 9 + 52

L = 61

Therefore, length = 61 m and width = 26 m.

x-3y=4

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