Will give brainliest. more than one answer for each question. question 1. find the equation of the line with a slope of -3, passing through the point (2, 5). a. y = -3x - 1 b. y = -3x + 11 c. y = -3x + 5 d. y = 2x + 5 multiple answers. question 2. find the equation of the line passing through the points (2, -1) and (-6, -5) a. y = 2x - 5 b. y = -1/2 x c. y = 1/2 x d. y = 1/2 x - 2 multiple answers

One

Slope

The general slope intercept equation for a line is

y = mx + b

If you are told outright what the slope is then you can write m = slope in this case - 3

So you have so far is y = -3x + b. Now you use the point to get the y intercept.

(2,5) means that when x = 2, y = 5. that allows you to solve for b

Y intercept

When x = 2, y = 5. Substitute that into the general equation with the slope.

5 = -3x + b            Put 2 in for x

5 = -3 * 2 + b         Multiply -3 * 2

5 = - 6 + b             Add 6 to both sides

5 + 6 = b

11 = b

Answer

y = -3x + 11

Two

This question is a little harder. You have to find the slope.

Slope Formula

Givens

Points (2, -1), (-6, - 5)

y2 = -1 ; y1 = -5; x2 = 2;  x1 = -6

Solve

m = (-1 - - 5)/(2 - - 6) = (-1 + 5)(2 + 6) = 4/8 = 1/2

Now find the y intercept. Use either one of the given points

(2,-1) when x = 2, y = - 1

y = 1/2 x + b      Show what you have so far. Put in x = 2 for x and y = - 1 for y

-1 = 1/2(2) + b    Multiply 2*1/2

-1 = 1 + b            Subtract 1 from both sides.

-1 -1 = b

- 2 = b

Answer

y = (1/2)x - 2 which is D

3.how is solving radical equations different than solving linear equations?

step-by-step explanation:

answer: h

step-by-step explanation: