The body of a 154-pound person contains approximately milligrams of gold and milligrams of aluminum. based on this information, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body?

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Complete Question

The body of 154-pound person contains approximately 2 x 10^-1 milligrams of gold and 6 x 10^1 milligrams of aluminum.

Based on this information, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body?

300 times

Step-by-step explanation:

From the above question, we are told:

The body of 154-pound person contains approximately 2 x 10^-1 milligrams of gold and 6 x 10^1 milligrams of aluminum.

We create a proportion

2 × 10^-1 mg of gold : 6 × 10^1 mg of aluminum

= 0.2 mg of gold : 60 mg of aluminum

Therefore, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body is calculated as:

60mg ÷ 0.2 mg

= 300

Therefore, the number of milligrams of aluminum in the body is 300 times the number of milligrams of gold in the body

answer: it actually depends on which is the independent variable and which is the dependent variable. let us say we're looking at a linear equation. y=2x+3. we theoretically could switch the equation to be x=(y-3)/2 and it would be the same line. so either a causes b or it can be that b causes a. so technically the answer is false

step-by-step explanation: