Write an equation for the following problem. then solve the equation and answer the problem. find three consecutive integers whose sum is 21.

Let the 3 numbers be x, x + 1 and x + 2, So:-

x + x + 1 + x + 2 = 21

3x = 21 - 3 = 18

x = 18/3 =  6

The 3 numbers are 6, 7 and 8  Answer

Let consecutive integers a-1; a; a+1, then

a-1+a+a+1=21

3а=21

a=7.

7-1=6; 7+1=8.

6; 7; 8.

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

25% is the answer