Solve the inequality. show your work. |4r + 8| ≥ 32

|4r + 8| ≥ 32

4r + 8 ≥ 32         or         4r + 8 ≤ -32       inside of absolute value could be + or -

4r       ≥ 24         or          4r       ≤ -40       subtracted 8 from both sides  

r       ≥  6           or            r       ≤ -10         divided both sides by 4

Graph: ← -10        6 →

Interval Notation: (-∞, -10] U [6, ∞)

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.