Mathematics, 09.07.2019 04:00 GlitterGayness
Given that y(t)=c1e4t+c2e−4ty(t)=c1e4t+c2e−4t is a solution to the differential equation y′′−16y=0y′′−16y=0, where c1c1 and c2c2 are arbitrary constants, find a function y(t)y(t) that satisfies the conditions
Answers: 1
![r^{2} -16=0 ⇒r^{2} =16 ⇒[tex]r_{1}=4 \\or \\ r_{2}=-4](/tpl/images/0068/0727/cc781.png)
ia solution of the given differential equation 
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Given that y(t)=c1e4t+c2e−4ty(t)=c1e4t+c2e−4t is a solution to the differential equation y′′−16y=0y′...
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