Find the derivative of g(t)=t2+5t at t=7 algebraically.

The power rule applies to each term.

... (d/dt)(t^n) = n·t^(n-1)

... g'(t) = 2t +5

... g'(7) = 2·7 +5 = 19

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92