Mathematics, 25.05.2020 15:57 QueenNerdy889
Let f (x) = 3x − 1 and ε > 0. Find a δ > 0 such that 0 < ∣x − 5∣ < δ implies ∣f (x) − 14∣ < ε. (Find the largest such δ.) What limit does this prove?
Answers: 2
, we want to find a 
such that 
. Then 
. 
. So, in this case, if 
we get that 
. 
. Note that f(5)=14, so this proves that f is continous at x=5.Another question on Mathematics
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Let f (x) = 3x − 1 and ε > 0. Find a δ > 0 such that 0 < ∣x − 5∣ < δ implies ∣f (x) − 14...
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