Arectangular garden is 5 feet longer than twice its width. it has a sidewalk 3 feet wide on two of its sides. the area of the sidewalk is 213 square feet. find the dimensions of the garden.

The length and width of the garden are 47 ft and 21 ft respectively.

Explanation

Suppose, the width of the garden is feet.

As the garden is 5 feet longer than twice its width, so the length will be:

So, the area of the garden

Now, the garden has a sidewalk 3 feet wide on two of its sides. That means, the length of the garden including the sidewalk and the width including the sidewalk

Given that, the area of the sidewalk is 213 ft². So the equation will be.....

So, the width of the garden is 21 feet and the length is

idek

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