Draw the product that is expected when hexanoyl chloride is treated with et2culi

Product formed is octan-3-one.

Explanation:

is a Gilman reagent. General formula of Gilman reagent is .

Where R is alkyl group or aryl group.

Gilman reagents react with the organo halides to replace halides with alkyl group or aryl group and this reaction is known as Corey–House synthesis.

When hexanoyl chloride is treated with , the chloride group of the hexanoyl chloride is substituted with the ethyl group of the to form octan-3-one with the removal of EtCu and LiCl.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2