×question 4 of 8 sara worked 28 hours last week. joan worked 6 hours less than sara, and erin worked half as many hours as joan. how many hours did sara, joan, and erin work last week?

Let

x> hours worked by Sara last week

y> hours worked by Joan last week

z> hours worked by Erin last week

we know that

x=28 hours > equation 1

y=x-6> equation 2

substitute the value of x in equation 2

y=28-6=22 hours

z=y/2> equation 3

substitute the value of y in the equation 3

z=22/2=11 hours

the answer is

Sara worked 28 hours last week

Joan worked 22 hours last week

Erin worked 11 hours last week

Sara worked for 28 hours last week.

Joan worked for 22 hours last week.

Erwin worked for 11 hours last week.

Step-by-step explanation:

Given :

Sara worked 28 hours last week.

Joan worked 6 hours less than Sara

Erin worked half as many hours as Joan.

To Find : How many hours did Sara, Joan, and Erin work last week?

Solution :

Since Sara worked for 28 hours last week .

And Joan worked for 6 hours less than Sara.

Then Joan worked for hours = 28-6 = 22 hours

Now we are also given that Erin worked for  half as many hours as Joan

So, Erin worked for hours = Joan hours /2 = 22/2 = 11 hours.

Thus, Sara worked for 28 hours last week.

Joan worked for 22 hours last week.

Erwin worked for 11 hours last week.

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

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