It took mark 6 hours to drive from his college to his home. the next week he drove the same distance from his home back to his college in 5 hours. if the average rate for his first trip was r miles per hour, what was the average rate for the second trip, in terms of r ?

We need to use the following formula of distance .

Distance= speed * time .

For the first time

distance = 6r

And let the average rate for the second time be s

So distance = 5s

Since distance remains same, so we get

6r=5s

Now we have to solve for s. And for that we need to get rid of 5, by dividing both sides by 5, that is

And that's the required average rate for the second trip .

i think it is 70

step-by-step explanation:

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.