What happens if 0.87 mol NaCl is dissolved in pure water creating 3.00 L of solution, what is its molarity of the resulting solution?

0.29 molL-1 or 0.29 M

Explanation:

Now we have to use the formula

n=CV

Where

n= number of moles = 0.87 moles

C= concentration of the solution (the unknown)

V= volume of the solution = 3.00L

Now having specified all parameters except the unknown (molarity if the sodium chloride solution) we can now proceed to find it.

C= n/V

C= 0.87mol/3.00L

C= 0.29 molL-1

0.29 mol/L

Explanation:

When sodium chloride (NaCl) is dissolved in water, it will dissociates to produce sodium ion (Na+) and chloride ion (Cl-) in solution as shown below:

NaCl —> Na+ + Cl-

Next, let us calculate the molarity of NaCl. This is illustrated below:

Mole of NaCl = 0.87 mole

Volume of solution = 3 L

Molarity =?

Molarity = mole of solute /Volume

Molarity = 0.87mole /3L

Molarity = 0.29 mol/L

Therefore, the molarity of NaCl is 0.29 mol/L

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