Write an exponential equation in the form y=ab^x whose graph passes through points (-3,24) and (-2,12).

The values to satisfy this equation would be a = 3 and b = .5.

In order to solve this we must first look at the equation with the second ordered pair in it. We can then solve for a.

y = ab^x

12 = ab^-2

12 =

12b^2 = a

Now that we have this solved for a, we can place that value in for a using the first ordered pair's values.

y = ab^x

24 = ab^-3

24 = 12b^2b^-3

24 = 12b^-1

24 =

24b = 12

b = .5

Now that we have the value of b, we can use either ordered pair and the b value to find a.

y = ab^x

12 = a(.5)^-2

12 = a(4)

a = 3

24b

europa2433

europa2433

step-by-step explanation:

translate k to n and reflect across the line containing jk.