Team one had twice as many workers as team two. the number of workers in team one is reduced by 5 and the number of workers in team two is reduced by 2. how many workers are there in each team now if there are 7 more workers in team one?

let

x> workers in team one initially

y> workers in team two initially

we know that

x=2y> equation 1

(x-5)=(y-2)+7> x-5= y+5> x=y+10> equation 2

equate equation 1 and equation 2

2y=y+10> y=10

x=2*10> x=20

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

with btw u said 100pts but it clearly says

i answerd and just got 10pts

no hate