Consider the expression below. for (x - 6)(x + 2) to equal 0, either (x - 6) or (x + 2) must . the values of x that would result in the given expression being equal to 0, in order from least to and

For (x - 6)(x + 2) to equal 0, either (x - 6) or (x + 2) must equal 0 . The values of x that would result in the given expression being equal to 0, in order from least to greatest, -2 and 6

Step-by-step explanation:

Given :(x - 6)(x + 2) =0

Solution :

The given equation :

This means either x-6 =0 or x+2=0

Now :

x-6 =0 or x+2=0

x=0+6 or x=0-2

x=6 or x= -2

Thus the values of x=6, -2

Hence  For (x - 6)(x + 2) to equal 0, either (x - 6) or (x + 2) must equal 0 . The values of x that would result in the given expression being equal to 0, in order from least to greatest, -2 and 6

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180