When a baseball is hit by a batter, the height of the ball, h(t), at time t, t=0, is determined by the equation h(t)=-16t^2+64t+4. if t is in seconds, for which interval of time is the height of the ball greater than or equal to 52 feet?

The time interval is in which the height of the ball greater than or equal to 52 feet.      

Step-by-step explanation:

We have given,When a baseball is hit by a batter, the height of the ball, h(t), at time t, t=0, is determined by the equation   where t is time in seconds.

We have to find, If t is in seconds, for which interval of time is the height of the ball greater than or equal to 52 feet?

Solution :  

The equation represented as

Where, t is time in seconds and h is the height.

We can solve the equation by putting h(t)=52

Therefore, The time interval is in which the height of the ball greater than or equal to 52 feet.

Now, We plot the graph of the given equation.

Refer the attached graph below.

For anyone who is lazy to read question above, it's D

Explanation:

Edg2020

all but the second one

step-by-step explanation:

cuz that one goes over 180

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