11 12 13 14 15 16 17 18 19 20 organizers of the town fair make a total of $706 from selling 164 hot dogs and 74 hamburgers at one of their concession stands. at their other concession stand, they make $884 by selling 256 hot dogs and 61 hamburgers. if the prices are the same at both concession stands, what is the price of a hot dog?

X= price of hotdog
y= price of hamburger

Set up equations for each stand. Multiply number of hotdogs and hamburgers sold by their prices (x and y) and add together to equal the total sold at each stand.

FIRST CONCESSION STAND
164x + 74y= $706

SECOND CONCESSION STAND
256x + 61y= $884

STEP 1
to solve by elimination, multiply first concession stand equation by 61; this will eliminate the y term

164x + 74y= $706
(61)(164x) + (61)(74y)= (61)(706)

10,004x + 4,514y= 43,066

STEP 2
multiply second concession stand equation by -74

256x + 61y= $884
(-74)(256x) + (-74)(61y)= (-74)($884)

-18,944x - 4,514y= -65,416

STEP 3
add step 1 & 2 equations together to solve for x

10,004x + 4,514y= 43,066
-18,944x - 4,514y= -65,416
y terms "cancel out"

-8,940x= -22,350
divide both sides by -8,940

x= $2.50 hotdog

ANSWER: $2.50 is the price of a hotdog.

Hope this helps! :)

1.17+3.99a. you combine the terms with a to create 3.99 and the 1.17 stays because it has no like terms or a variable