Calculate the pH of a 0.35 mol/L solution of butanoic acid

2.6

Explanation:

Step 1: Given and required data

Step 2: Calculate the acid dissociation constant (Ka) of butanoic acid

We will use the following expression.

pKa = -log Ka

Ka = antilog - pKa

Ka = antilog -4.82 = 1.51 × 10⁻⁵

Step 3: Calculate [H⁺] of the solution

For a weak acid, we can use the following expression.

[H⁺] = √(Ca × Ka)

[H⁺] = √(0.35 × 1.51 × 10⁻⁵) = 2.3 × 10⁻³ M

Step 4: Calculate the pH of the solution

pH = -log [H⁺] = -log 2.3 × 10⁻³ = 2.6

screening

explanation:

the law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. because atoms are only rearranged in a chemical reaction, there must be the same number of sodium atoms and chlorine atoms in both the reactants and products