Someone a spinner has five sectors of equal size. the sectors are labeled 1, 2, 3, 4, and 5. the spinner is spun twice. x is the number of times an odd number is spun.  drag each bar on the horizontal axis to the correct location to create a probability distribution for  x.

Because the sectors are of equal size, each sector has the same probability of happening.
So for every number, you have a probability of 0.2 of it appearing.

Because you have three odd numbers, the probability to land on an odd number on each spin is 0.6. You can also say that the probability to not have an odd number is 0.4.

So what is the probability to have 0 odd number in two spins?

What is the probability to have 1 odd number in two spins? You can have one odd number on the first or one odd on the second spin, that is why we add the probabilities.

What is the probability to have 2 odd numbers in two spins?


To verify if we did a good job, we add all the probabilities. We should get 1.
.

So to slide your bars, you slide them up to the number I gave you for each case.

You must find the surface of the block therefore 98187 dived by 5628 = 583m squared

Your answer should be “b” i truly hope i could ! good luck (: