Amodel rocket is launched from the ground with an initial velocity of 120 feet per second. the height of an object h, in feet, after t seconds, with initial velocity v0 and initial height h0 is given by h(t)=−16t2+v0t+h0 . what is the approximate maximum height the rocket reaches?

The rocket will reach a maximum height of 225 feet from the ground in 3.75 seconds.      

Step-by-step explanation:

We are given the following information in the question:

Initial velocity = = 120 feet per second

Initial heigth =

h(t) is a function of t that gives height of the rocket at time t, initial velocity . intial height .

Differentiating h(t) with respect to t, we get:

Equating the first derivative to zero,

Again differentiating, h(t) with respect to t,

Hence, h(t) will have a local maxima by double derivative test.

Maximum height attained by rocket =

Hence, the rocket will reach a maximum height of 225 feet from the ground in 3.75 seconds.

1 ?

step-by-step explanation:

u said 1+1+1+1+1+1+1+1+1+1+1+1*0 so ur adding 1 but then multiplying by 0 so its 0 but then u said 1*0+1 so now ur adding 1 so the answer is juan ?

~leah