Shelby graphs the function f(x)=(x-3)2 -1. which statements are true about the graph? check all that apply

While your statements are missing, there are a few things we can tell about the graph from the equation:

The vertex is at (3, -1).  We know this because the equation is in vertex form,
y=a(x-h)²+k, where (h, k) is the vertex.

The graph opens upward and has a minimum.  This is because there is no negative before the squared term.

The y-intercept of the graph is at (0, 8).  We know this because if we substitute 0 for x, we have
y=(0-3)²-1 = (-3)²-1 = 9-1 = 8