What is the value of sinθ given that (−6, −8) is a point on the terminal side of θ ?

Step-by-step explanation:

Let a=-8

b=-6

In triangle , by using Pythagoras theorem,

=+

r=

r=

r=

r=

r=10

by using trigonometric ratio,

sinθ =

sinθ =

sinθ =

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)