What is the area of ∆abc to the nearest tenth of a square meter?

The remaining side using cosine theorem is:
 BC ^ 2 = 36 ^ 2 + 36 ^ 2 - 2 * 36 * 36 * cos (65)
 BC = root (1496.573466)
 BC = 38.68557181
 Then, for the area we have:
 A = root (s (s-a) * (s-b) * (s-c))
 s = (a + b + c) / 2
 Substituting:
 s = (36 + 36 + 38.68557181) / 2
 s = 55.34278591
 A = root (55.34278591 * (55.34278591-36) * (55.34278591-36) * (55.34278591-38.68557181))
 A = 587.2874463
 Rounding off we have:
 A = 587.3
 
 A = 587.3