The flame temperature in an automobile engine is 1699 °f, and the exhaust is emitted at 229 °f. what is the carnot efficiency of the engine?

Solution:

η =  Efficiency ; T(hot) =Temperature of the Hot source ; T(cold) = Temperature of the Cold Sink ;

η = 1 – {T(cold)/T(hot)}

η = 1 – {229 / 1699}

η = 0.6809748595199822 x 100

η = 68.09 %

The answer is 68.09 %,  you can use the Carnot Thermal efficiency Calculator in the Internet.

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