In World War II, the Germans made use of an electromechanical rotor-based cipher system known as . A. the Enigma machine B. Kerckhoffs' principle C. symmetric cryptography D. the Feistel function 2 points QUESTION 4 Making two copies of a suspect's drive, using two different imaging tools, can help to prove that evidence is accurate. True False 2 points QUESTION 5 How you will gather evidence and which tools are most appropriate for a specific investigation are part of . A. the expert report B. a forensic analysis plan C. a curriculum vitae D. the rules of evidence 2 points QUESTION 6 What is the definition of transposition in terms of cryptography

What is outfitting a workplace with video in a technology

Install and use wireshark program ( send back screen shots and other vital information) case project 3-2: decode a tcp segment in a wireshark capture in this chapter, you walked through tcp segment to interpret the data included in its header. in this project, you use wireshark to capture your own http messafes, examine the tcp headers, and practice interpreting the data you'll find there. 1. open wireshark and snap the window to one side of your screen. open a browser and snap that window to the other side of your screen so you can see both windows.

When making changes to optimize part of a processor, it is often the case that speeding up one type of instruction comes at the cost of slowing down something else. for example, if we put in a complicated fast floating-point unit, that takes space, and something might have to be moved farther away from the middle to accommodate it, adding an extra cycle in delay to reach that unit. the basic amdahl's law equation does not take into account this trade-off. a. if the new fast floating-point unit speeds up floating-point operations by, on average, 2ă—, and floating-point operations take 20% of the original program's execution time, what is the overall speedup (ignoring the penalty to any other instructions)? b. now assume that speeding up the floating-point unit slowed down data cache accesses, resulting in a 1.5ă— slowdown (or 2/3 speedup). data cache accesses consume 10% of the execution time. what is the overall speedup now? c. after implementing the new floating-point operations, what percentage of execution time is spent on floating-point operations? what percentage is spent on data cache accesses?