The parent_directory function returns the name of the directory that's located just above the current working directory. Remember that '..' is a relative path alias that means "go up to the parent directory". Fill in the gaps to complete this function. import os
def parent_directory():
# Create a relative path to the parent
# of the current working directory
dir = os. getcwd()
relative_parent = os. path. join(dir, ___)
# Return the absolute path of the parent directory
return os. path. dirname(relative_parent)
print(parent_directory())

Functions are collection of code segments that are executed when called or evoked.

The complete function in Python, where comments are used to explain each line is as follows:

#This imports the os module

import os

#This defines the parent_directory function

def parent_directory():

   #This gets file directory

   dir = os.getcwd()

   #This gets the complete directory

   relative_parent = os.path.join(dir)

   #This returns the directory name

   return os.path.dirname(relative_parent)

print(parent_directory())

Read more about python functions at:

Following are the complete code to this question:

import os #import package  

def parent_directory():#defining a method parent_directory

   dir = os.getcwd()#defining dir that stores the getcwd method value  

   relative_parent = os.path.join(dir) #defining relative_parent variable that uses join method to adds directory

   return os.path.dirname(relative_parent)#use return keyword to return directory name

print(parent_directory())#use print method to call parent_directory method

Output:

/

Note:

This program is run the online compiler that's why it will return "/"

Explanation:

In the given Python code, we import the "os" package, after that a method "parent_directory" is defined, which uses the dir with the "getcwd" method that stores the current working directory.  

i'm so sorry that's not a question and this isn't an answer