How many grams of water are needed to react with 44.9 grams of li2o?

The  grams  of  water   needed  to  react  with  44.9  grams  of Li2O  is  calculated as  follows 

write  the  equation  for  reaction
Li2O  +H2O  = 2LiOH

find  the  moles  of  Li2O  =  mass/molar   mass
=  44.9/29.9  =  1.5  moles

by  use  of  reacting  ratio  between   Li2O to  H2O  which  is  1:1  the  moles  of  H2O  is  therefore =  1.5  moles

mass  is  therefore  =  moles  x molar  mass
= 1.5 mol  x 18 g/mol  =  27  grams

Ok so co(g) is not pronoused that. the only clue is that youpronouse it the oppisote way. 

We first assume that this gas is an ideal gas where it follows the ideal gas equation. the said equation is expressed as: pv = nrt. from this equation, we can predict the changes in the pressure, volume and temperature. if the volume and the temperature of this gas is doubled, then the pressure still stays the same.