Which factor causes a decrease in the rate of dissolution? decreasing the amount of solute
increasing the stirring of the solution
decreasing the surface area of the solute
increasing the temperature of the solvent

The correct option of the first option

Explanation:

Dissolution of a solute in a solution is the process in which the solute interacts with the solvent leading to the disappearance of the solute to form a solution. Rate of dissolution is primarily affected by three factors namely

Stirring of the solution: Stirring the solution causes the solute to interact more with the solvent, thus increasing the rate of dissolution.

Surface area of the solute: The smaller the surface area of the solute, the more easier it is for it (the solute) to interact with the solvent. Hence, the smaller the surface area, the faster the rate of dissolution.

Temperature of the solvent: An increase in temperature of the solvent causes the generally causes more things to dissolve in this solvent due to increased energy of molecules in the solvent, which causes the molecules of the solute and solvent to interact more.

A decrease in the amount of solute will reduce the amount of interaction the solute (since it is in lesser quantity) have with the solvent hence the rate of dissolution will also be low (even though a solution will still be formed).

it have destructive character

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.