Chemistry, 25.07.2019 02:30 brittanyfox411
When ethyl acetoacetate (ch3coch2co2ch2ch3) is treated with one equivalent of ch3mgbr, a gas is evolved from the reaction mixture, and after adding aqueous acid, ethyl acetoacetate is recovered in high yield. identify the gas formed and explain why the starting material was recovered in this reaction. be sure to answer all parts. the gas formed is: o2 h2 ch4 co2 this occurs because: addition of a methyl group through nucleophilic addition destabilizes the ester group. because of the acidic proton, ch3mgbr reacts as a base and proton transfer occurs rather than nucleophilic addition. aqueous acid adds an oxygen to the carbanion formed releasing h2 gas. addition of aqueous acid disrupts the anhydride bond which reforms after decarboxylation?
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When ethyl acetoacetate (ch3coch2co2ch2ch3) is treated with one equivalent of ch3mgbr, a gas is evol...
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