A2.00-l reaction vessel, initially at 298 k, contains chlorine gas at a partial pressure of 337 mmhg and fluorine gas at a partial pressure of 729 mmhg. identify the limiting reactant and determine the theoretical yield of clf3 in grams.

The theoretical yield of is 2.24 g

Explanation:

The equation given by ideal gas follows:

         .......(1)

where, P = pressure of the gas

V = Volume of the gas

T = Temperature of the gas

R = Gas constant =

n = number of moles of gas

We are given:

Putting values in equation 1, we get:

We are given:

Putting values in equation 1, we get:

The chemical equation for the reaction of chlorine gas and fluorine gas follows:

By Stoichiometry of the reaction:

3 moles of fluorine gas reacts with 1 mole of chlorine gas.

So, 0.0363 moles of fluorine gas will react with = of chlorine gas

As, given amount of chlorine gas is more than the required amount. So, it is considered as an excess reagent.

Thus, fluorine gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

3 moles of fluorine gas produces 2 moles of

So, 0.0363 moles of fluorine gas will produce = of

Molar mass of = 92.45 g/mol

Moles of = 0.0242 moles

Putting values in above equation, we get:

Hence, the theoretical yield of is 2.24 g