A25.00 ml sample of an aqueous solution of ba(oh)2 requires 18.45 ml of 0.01500 m hcl (aq) for its neutralization. what is the molarity of the ba(oh)2 solution?

5.54 x 10⁻³ M

Given:

Neutralization reaction between:

Question:

What is the molarity of the Ba(OH)₂ solution?

The Process:

Let us say the molarity of the Ba (OH)₂ solution as x M.

Step-1: prepare moles for each reagent

Step-2: neutralization

We use the ICE table to see how neutralization occurs between acid and base.

Balanced reaction:

Initial:               25x                0.277              -                    -

Change:    - ¹/₂ · (0.277)        -0.277      +¹/₂ · (0.277)     +0.277

Equlibrium:        -                       -           +¹/₂ · (0.277)    +0.277

Step-3: calculate the molarity of the Ba(OH)₂ solution.

We consider Ba (OH) from the initial, change, and equilibrium stages.

Thus, the molarity of the Ba(OH)₂ solution is 5.54 x 10⁻³ M.

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Alternative Steps

Neutralization:

Thus the same results were obtained. The molarity of Ba (OH) ₂ solution is 5.54 x 10⁻³ M.

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