White phosphorus, p4, is prepared by fusing
calcium phosphate, ca3(po4)2, with carbon, c,
and sand, sio2, in an electric furnace.
2ca3(po4)2(s) + 6sio2(s)
+ 10c(s) --> p4(g)
+ 6casio3(l) + 10co(g)
how many grams of calcium phosphate are required to give
30.0 g of phosphorus?
think it's 150. g ca3(po4)2 (am i right or wrong? explain, )

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