According to statcounter, Google Chrome browser controls 62.8% of the market share worldwide. A random sample of 70 users was selected. What is the probability that 35 or more from this sample used Google Chrome as their browser

The probability that 35 or more from this sample used Google Chrome as their browser is 0.9838.

Step-by-step explanation:

We are given that according to Statcounter, the Google Chrome browser controls 62.8% of the market share worldwide.

A random sample of 70 users was selected.

Let = sample proportion of users who used Google Chrome as their browser.

The z-score probability distribution for the sample proportion is given by;

                              Z  =    ~ N(0,1)

where, = sample proportion = = 0.50

            p = population proportion = 62.8%

            n = sample of users = 70

Now, the probability that 35 or more from this sample used Google Chrome as their browser is given by = P( 0.50)

       P( 0.50) = P( ) = P(Z -2.14)

                           = P(Z 2.14)  = 0.9838

The above probability is calculated by looking at the value of x = 2.14 in the z table which has an area of 0.9838.

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

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step-by-step explanation:

just for that im not answering