Calculate the temperature, in k, of 2.20 moles of gas occupying 3.30 l at 3.50 atm.

From  idea  gas  equation  that is   PV=nRT
T= temperature  in kelvin
R=gas   cosntant(0.0821atm/k/mol)
P=pressure(3.5atm)
V=volume 3.30L
n=number  of  moles (2.20mole)
T  is  therefore  =PV/nR
T={(3.50 x3.30) /(2.20 x 0.0821)}=63.95k

Answer///an early form of the atomic theory; dalton atomic theory;