Under what circumstances is isolation necessary when dealing with hazardous material events?

When the material is explosive, oxidizing, poisonous, radioactive, corrosive, biohazard material.

Explanation:

If the material is explosive, precautions must be high, and insulation serves to prevent explosion.

If the material is oxidizing or corrosive, the insulation serves to prevent spillage and damage to the structure.

If the material is poisonous, radioactive or biohazard, it must be insulated to prevent damage to the environment, structures, and nearby personnel operating it.

Have a nice day!

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j